向函数传递结构

作者：追风剑情发布于：2020-1-19 19:49 分类：C

示例

//Visual Studio中加上这句才可以使用scanf()
//否则只能使用scanf_s()
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#include <ctype.h>
//malloc()、free()
#include <stdlib.h>
#include <time.h>
 
#define FUNDLEN 50
 
struct funds {
	char bank[FUNDLEN];
	double bankfund;
	char save[FUNDLEN];
	double savefund;
};
 
double sum(double, double);
double sum1(const struct funds *); /* 参数是一个指针 */
double sum2(struct funds moolah); /* 参数是一个结构 */
 
//argc: 参数个数 argv[]: 参数数组
//int main(int argc, char **argv)
int main(int argc, char *argv[])
{
	struct funds stan = {
		"Garlic-Melon Bank",
		4032.27,
		"Lucky's Savings and Loan",
		8543.94
	};
 
	// 传递结构成员
	printf("Stan has a total of $%.2f.\n",
		sum(stan.bankfund, stan.savefund));
 
	// 传递结构的地址
	printf("Stan has a total of $%.2f.\n",
		sum1(&stan));
 
	// 传递结构
	printf("Stan has a total of $%.2f.\n",
		sum2(stan));
 
	system("pause");
	return 0;
}
 
double sum(double x, double y)
{
	return (x + y);
}
 
double sum1(const struct funds * money)
{
	return (money->bankfund + money->savefund);
}
 
double sum2(struct funds moolah)
{
	return (moolah.bankfund + moolah.savefund);
}